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CGP EDU Academic Team
Published on: August 13, 2026
The first order rate constant for the decomposition of CaCO 3 at 700K is 6.36x10 -3 s -1 and activation energy is 209kJ mol -1 . Its rate constant (in s -1 ) at 600K is 
. The value of x is ____. (Nearest integer) [Given R = 8.31 J K −1 mol −1 ; log 6.36 × 10 −3 = −2.19, 10 −4.79 = 1.62 × 10 −5 ]
Text Solution
Verified by ExpertsThe correct answer is:
16
(16)
K 700 = 6.36 × 10 −3 s −1 ;
K 600 = x × 10 −6 s −1
E a = 209 kJ/mol
Applying ;
⇒ K 600 = 10 −4.79 = 1.62 × 10 −5
= 16.2 × 10 −6
= x × 10 −6
⇒ x = 16
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