Published by:
CGP EDU Academic Team
Published on: August 13, 2026
The minimum voltage required to electrolyse alumina in the Hall-Heroult process is Given, 
(Al 2 O 3 ) = -1520 klmol -1
(CO 2 ) = -394 kJ mol -1
Text Solution
Verified by ExpertsThe correct answer is:
B
2A1 2 O 3 (s) + 3C 
4A1 (s) + 3CO 2 (g)
= -3 x 394-2 (-1520)
= -1182 + 3040
= +1858 kJ
G° = -nFE°
1858 x 1000 = -12 x 96500 x E°
E ° = -1.60V
Thus, voltage requires =1.60 V
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