If the unit cell of a mineral has cubic close packed (ccp) array of oxygen atoms with m fraction of octahedral holes occupied by aluminium ions and n fraction of tetrahedral holes occupied by magnesium ions, m and n, respectively, are
Text Solution
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No. of oxygen atoms per unit cell in ccp = 4 (O 2- )
No. of octahedral voids per unit cell = 4 (Al 3+ )
No. of Tetrahedral voids per unit cell = 8 (Mg 3+ )
Total negative charge due to oxygen atoms = 8
Net charge must be zero.
m4(3) + 2n(8) + 4(-2) = 0
3m + 4n = 2
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