The rate of decomposition for methyl nitrite and ethyl nitrite can be given in terms of rate constant k 1 and k 2 respectively. The energy of activation for the two reactions are 152.30 kJ mol -1 and 157.7 kJ mol -1 as well as frequency factors are 10 13 and 10 14 respectively for the decomposition of methyl and ethyl nitrite. Calculate the temperature at which rate constant will be same for the two reactions.
Text Solution
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For methyl nitrite k 1 = 10 13 e [-152300/(8.314xT)]
For ethyl nitrite k 2 = 10 14 e [-157700/(8-314xT)]
If k 1 = k 2 then
10 13 e [-152300/(8-314xT)] = 10 14 e [-157700/(8-314xT)]
Or 2.303 log 10= 
T = 282 K
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