P 4 O 6 reacts with water according to equation P 4 O 6 + 6H 2 O 
4H 3 PO 3 . Calculate the volume of 0.1 M NaOH (in mL ) solution required to neutralise the acid formed by dissolving 1.1 g of P 4 O 6 in H 2 O?
Text Solution
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400.00
P 4 O 6 + 6H 2 O 
4H 3 PO 3 ...... (i)
Neutralization :
H 3 PO 3 + 2NaOH 
[Na 2 HPO 3 + 2H 2 O] x 4 ....... (ii)
Adding Eqs. (i) and (ii)
.....(iii)
Number of moles of P 4 O 6 ,
(Molar mass P 4 O 6 = (4 x 31) + (6 x 16) = 220
Product formed by 1 mole of P 4 O 6 is neutralized by 8 moles NaOH
Product formed by 
moles of P 4 O 6 will be neutralized by NaOH
moles NaOH
Given, Molarity of NaOH = 0.1 M = 0.1 mol/L
Molarity = 
or 400mL
400 mL NaOH is required.
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