Copper sulphate solution (250 mL) was electrolysed using a platinum anode and a copper cathode. A constant current of 2 mA was passed for 16 min. It was found that after electrolysis the absorbance of the solution was reduced to 50% of its original value. Concentration of copper sulphate in the solution to begin with is x 
10 -5 . Find the valu of x
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8
The number of faraday's passed = 
= 1.99 x 10 -5
number of gram equivalent of Cu 2+ deposited as Cu(s)
= 1.99 x 10 -5
number of moles of Cu 2+ deposited
Absorbance is directly proportional to 
.
No. of moles of Cu 2+ initially present = 2 x 10 -5 moles
= 8 x10 -5 M
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