The solubilities of AgBr in water, in 0.01 M CaBr 2 , 0.01 M KBr and in 0.05 M AgNO 3 are S 1 ,S 2 ,S 3 and S 4 respectively. Then the order of solubilities is
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S 1 > S 3 > S 2 > S 4
Solubility of AgBr in 0.01 M CaBr 2 (s 2 ) ......(i)
CaBr 2 is a strong electrolyte and dissociates completely to give common ion Br - CaBr 2 
Ca
2+ + 2Br - 0.01 M
0.01M 0.02M
AgBr(s) 
Ag + (aq)+Br - (aq); K sp
S 2 0.02+S 2 
S 2 x 0.02 = K sp
-0.02 or S 2 = 50 K sp
Similarly, KBr gives common ion Br - And AgNO 3 gives common ion Ag
+ and we can calculate
S 3 = 100K sp ......(iii)
And S 4 = 20 K sp ......(iv) respectively
From (i), (ii), (iii) and (iv)
S 1 > S 3 > S 2 > S 4
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