Published by:
CGP EDU Academic Team
Published on: August 14, 2026
The dissociation equilibrium of a gas AB 2 can be represented as,
2AB 2 (g)
2AB(g) + B 2 (g)
The degree of dissociation is x and is small as compared to 1. The expression relating the degree of dissociation (x) with equilibrium constant K p and total pressure P is:
Text Solution
Verified by ExpertsThe correct answer is:
D

2AB 2 (g)
2AB (g) + B 2 (g)
At equilibrium 2(1 - x) 2x x
Total moles = (2 + x)
Partial pressures



(x is small)



Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
Suitable conditions for melting of ice are:
NH 4 HS (s) NH 3 (g) + H 2 S(g) In the above reaction, if the pressure at equilibrium and at 300 K…
Calculate A r G for the reaction at 27° C
H 2 (g) + 2Ag + (aq) 2Ag (s) + 2H + (aq)
Given : = 0.5 …
The equilibrium constant for a reaction A + B C+ Dis l x 10 -2 at 298 K and is 2 at 273 K. The che…
At 300K,
A Product G° T = -200kJmol -1 B Product G° T = -50kJmol
-1 Thus, the ratio of equilibr…
Ammonium sulphide and ammonium selenide on heating dissociates as
(NH 4 ) 2 S(s) 2NH 3 (g)+ H 2 S(…