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CGP EDU Academic Team
Published on: August 14, 2026
0.1 M KMnO 4 is used for following titration. What volume of the solution in mL will be required to react with 0.158 g of Na 2 S 2 O 3 ?
Not balanced: 
Text Solution
Verified by ExpertsThe correct answer is:
A
'n' factor of Na 2 S 2 O 3 = 8
'n' factor of KMnO 4 = 3
m.eqof Na 2 S 2 Os = m.eqof KMnO 4
x 8 x 1000 = 0.1 x V x 3
V = 26.7 mL
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