To a 25 mL H 2 O 2 solution, excess of acidified solution of potassium iodide was added. The iodine liberated required 20 mL of 0.3 N sodium thiosulphate solution. Calculate the volume strength of H 2 O 2 solution and report your answer by multiplying it with 1000.
Text Solution
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Applying normality equation, underset(H_2 O_2) ubrace (N_1 V_1) = underset (Na_2 S_2 O_3) ubrace(N_2 V_2)
Strength of 
68 g of 
produce 
at N.T.P. 
4.08 g of 
will produce 
at N.T.P. 
Now 4.08 g of 
are present in 1000 mL of solution.
of 
solution give 1344 mL of 
at N.T.P.
of 
solution will give 
of 
at N.T.P.
Volume strength of 
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