Published by:
CGP EDU Academic Team
Published on: August 14, 2026
The value of Iog 10 K for a reaction A 
B is
(Given 
H° 298K = -54.07 kJ mol -1 ,
S° 298K = 10 JK -1 mor -1 and
R = 8.314 JK -1 mol -1 , 2.303 x 8.314 x 298 = 5705 )
Text Solution
Verified by ExpertsThe correct answer is:
B
10
For the equilibrium, A 
B
G° = -2.303 RT log 10 K (K is equilibrium constant)
-2.303 RT Iog 10 K = 
H° - T 
S°
2.303 RT Iog 10 K = T 
S° - 
H°
Hence is correct option.
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