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CGP EDU Academic Team
Published on: August 13, 2026
1 Mole of CO 2 gas at 300 K expanded under the reversible adiabatic condition such that its volume becomes 27 times. The magnitude of work done (in kJ/mol) is: (Given 
= 1.33 and C v = 25.10 Jmol -1 K -1 for CO 2 ) report your answer by rounding it up to nearest whole number
Text Solution
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CHECK THE SOLUTION.
5
Number of moles = 1
T 1 = 300 K
V 2 = 27V 1
T 2 = 100 K
Adiabatic condition, q = 0; 
E = w = nC v (T 2 -T 1 )
w = 1 x 25.10 (100-300) = -5020 J/mole
w = -5.02 kJ/mole
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