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CGP EDU Academic Team
Published on: August 14, 2026
3.0 molal aqueous solution of an electrolyte A 2 B 3 is 50 % ionised. The boiling point of the solution at 1 atm is: [K b (H 2 O) = 0.52 Kkgmol -1 ]
Text Solution
Verified by ExpertsThe correct answer is:
B
377.68 K
A 2 B 3 (aq) -^ 2A 3+ (aq) + 3B 2 ~ (aq)
n=5
T b =i.K b .m
=[l + (n-1) 
]K b .m.
= [l + 4 
]K b .m.
= [1 + 4(0.5)]0.52 x 3
= (1 + 2)(0.52) x 3
= 4.68
A b = 373 + 4.68 = 377.68K
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