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CGP EDU Academic Team
Published on: August 13, 2026
Depression in freezing point of 0.01 molal aqueous solution of HA is 0.01924 K. The pK a value of HA is [Given = molarity = molality, [K f (H 2 O) = 1.85 Kkg mol -1 , log 2 = 0.3]
Text Solution
Verified by ExpertsThe correct answer is:
4
4.80
T f = i x m x K f
0.01924 = i x 0.01 x 1.85
i= 1.04
i = 1 + 
(n - 1)
1.04 = l+ 
(2-l)
= 0.04
K a = 
2 c = (0.04) 2 x 0.01 = 16 x 10 -6
pK a = 4.8
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