100 g of liquid A (molar mass 140 g mol -1 ) was dissolved in 1000 g of liquid B (molar mass 180 g mol -1 ). The vapour pressure of pure liquid B was found to be 500 torr. Calculate vapour pressure of A (in torr) the solution if the total vapour pressure of the solution is 475 torr.
Text Solution
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Step I: Calculation of vapour pressure of pure liquid A 
Number of moles of liquid A
Number of moles of liquid B
Mole fraction of A
Mole fraction of B(x B ) = 1 - 0.1139 = 0.8861
Vapour pressure of pure liquid B, 
= 500 torr
Total vapour pressure of solution (p) = 475 torr
According to the Raoult's law
475 torr = 
x (0.1139) + 500 torr x (0.8861)
475 torr = 
x (0.1139) + 443.05 torr
Step II : Calculation of vapour pressure of A in the solution (p A )
According to Raoult's law,
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