C(s) + O 2 (g) 
CO 2 (g) + 400 kJ
C(s) + 
O 2 (g) 
CO(g) + 100 kJ
When coal of purity 60% is allowed to burn in presence of insufficient oxygen, 60% of carbon is converted into 'CO' and the remaining is converted into ‘ CO 2 ’
The heat generated when 0.6 kg of coal is burnt is
Text Solution
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C(S) + O 2 (g) 
CO 2 (g) + 400 kJ
1 g mole
C(s) + 
O 2 (g) 
CO(g) + 100kJ ....(II)
0.6 x 1000
= 600 gm
(Pure Carbon)
mole (Pure Carbon)
Carbon converted into CO 2 = 
= 12 mole
and carbon converted in CO = 30 x 
= 18 mole
Energy generated during II equation
= 18x100
=1800kJ
Energy generated during I st reaction.
=12 x400
= 4800
Total = 1800 + 4800 = 6600 kJ
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