Home Chemistry Ionic Equilibrium JEE Main 2020 3 gram of acetic acid is mixed in 250 mL of …
Chemistry Ionic Equilibrium JEE Main 2020 Numeric Response
Published on: August 14, 2026

3 gram of acetic acid is mixed in 250 mL of 0.1 M HCl. This mixture is now diluted to 500 mL∙20mL of this solution is now taken in another container. of 5M is added to this. Find the of this solution. .

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The correct answer is:
522

(522)

mole of acidic acid in 20 L

mole of in 20 L

mole of

2 3/2 0 0

0.5 0 3/2 –

Final ans :

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