224 mL of 
at 298 K and 1 is passed through 100 mL of 0.1MNaOH solution. The non-volatilesolute produced is dissolved in 36 g of water. The lowering of vapour pressure of solution (assuming thesolution is dilute) 
is 
mm of is of Hg, the value of x is (round off to nearest integer)
Text Solution
Verified by Experts0
(0)
The balanced equation is
Moles of NaOH = molarity × volume (in liter)
moles
Here NaOH is limiting Reagent 2 mole NaOH → 1 mole 
0.01 mole NaOH → 
mole 
Moles of 
mole
Moles of 
moles
According to RLVP
Lowering in pressure = 0.18 mm of Hg of lowering in pressure 
mm of Hg
X = 18
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems