An element undergoes a reaction as shown :
, energy released = 30 .87 eV/ atom. If the energy released is used to dissociate 4 gms of H 2 molecules, equally into H + and H* , where H* is excited state of H atoms where the electron travels in orbit whose circumference equal to four times its de Broglie's wavelength. Determine the least moles of X that would be required:
Given: I.E. of H = 13 .6 eV / atom bond energy of H 2 =4 .526 eV / molecule.
Text Solution
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Total energy requirement per molecule of H 2 :
Binding energy =4.526 eV
I.E = 13.60 eV
According to de Broglie's explanation of Bohr's orbit
As per question, 
Thus, electron is excited to the 4 th Bohr orbit
Excitation energy = E 4 – E 1 = -0 .85 - (-13.60) = 12.75 eV
Thus, total eenergy requirement per molecule = 13 .60 +12 .75 +4 .526 
30.87 eV
Thus, 1 molecule of H 2 will be dissociated by 1 atom of X
Therefore, (4 gH 2 ) 
2 moles of H 2 molecules will be dissociated by 2 moles of X.
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