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CGP EDU Academic Team
Published on: August 14, 2026
Ionization energy of He + is 19.6 × 10 –18 J atom –1 . The energy of the first stationary state (n = 1) of Li 2+ is:
Text Solution
Verified by ExpertsThe correct answer is:
B
I.E. of He + = 19.6 × 10 –18 J atom –1
I.E. = – E 1
E 1 for He + is = – 19.6 × 10 –18 J atom –1
= 
⇒ 
= 
E 1 (Li 2+ ) = 
= – 44.1 × 10 –18
= – 4.41 × 10 –17 J atom –1
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