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CGP EDU Academic Team
Published on: August 13, 2026
When a certain metal was irradiated with light frequency 1.6 × 10 16 Hz, the photo electrons emitted had twice the kinetic energy as did photoelectrons emitted with frequency 1 × 10 16 Hz when the same metal was irradiated with light, then threshold frequency x × 10 15 Hz. Find "x".
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
By photoelectric effect. h ν = h ν 0 + KE
∴ KE 1 = h( ν 1 – ν 0 ) .....
KE 2 = h( ν 2 – ν 0 )= KE 1 /2 ......
Dividing equation by we have 
2.0 × 10 16 –2 ν 0 = 1.6×10 16 – ν 0
ν 0 = 4 × 10 15 Hz
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