An element undergoes a reaction as shown:
x + e – → x – energy released = 30.87 eV
If the energy released, is used to dissociate 12 g of H 2 molecules, equally into H + and H*, where H* is an excited state, in which the electron travels a path length equal to four times it’s debroglie wavelength.
Determine the least amount (in moles) of ‘x’ that would be required.
Given: I.E. of H = 13.6 eV/atom, Bond energy of H 2 = 4.526 eV/molecule.
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
x + e – → x –
energy released = E.A 1 + E.A 2 = 30.87 eV/atom
Let no. of moles of X be a
∴ a × N a × 30.87 = 6 × N a × 4.526 + 6 × N a ×13.6 + 6 × N a × 12.75 ⇒ a = 6 moles
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