Published by:
CGP EDU Academic Team
Published on: August 13, 2026
O 2 undergoes photochemical dissociation into 1 normal oxygen atom (O) and more energetic oxygen atom O*. If (O*) has 1.967 eV more energy than (O) and normal dissociation energy of O 2 is 498 kJmol –1 , what is the maximum wavelength effective for the photo chemical dissociation of O 2 ?
Text Solution
Verified by ExpertsThe correct answer is:
C
O 2 → O + O* ; Dissociation energy = 468 kJ mol –1
= 
J mol –1 = 8.27 × 10 –19 J.molecules –1
Extra energy of the excited atom = 1.967 eV
= 1.967 × 1.6 × 10 –19 J = 3.15 × 10 –19 J atom –1
λ = 
= 
= 174 × 10 –9 m
Thus, λ = 174 nm.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
Which of the following atoms and ions are isoelectronic i.e . have the same number of electrons wit…
Atoms consists of protons, neutrons and electrons. If the mass of neutrons and electrons were made …
The increasing order (lowest first) for the values of (charge/mass) for electron (e), proton ( ),…
The electronic configuration of a dipositive metal is 2, 8, 14 and its atomic weight is 56 a.m.u. …
The ratio of the energy of a photon of wavelength radiation to that of radiation is
Discovery of the nucleus of an atom was due to the experiment carried out by