Explanation: 2 Ag + S → Ag 2 S

2 × 108 g of Ag reacts with 32 g of sulphur

10 g of Ag reacts with × 10 = > 1 g

It means ‘S’ is limiting reagent

32 g of S reacts to form 216 + 32 = 248 g of Ag 2 S

1 g of S reacts to form = = 7.75 g

Alternately

n eq of Ag = = 0.0925 n eq of S = = 0.0625 (n eq = number of equivalents)

Since n eq of S is less than n eq of Ag

⇒ 0.0625 eq of Ag will react with 0.0625 eq of S to form 0.0625 eq of Ag 2 S

Hence, amount of Ag 2 S = n eq × Eq. wt. of Ag 2 S = 0.0626 × 124 = 7.75 g