When 1 mole of A reacts with 
mole of B 2 (A + 
B 2 → AB), 100 Kcal heat is liberated and when 1 mole of A reacted with 2 mole of B 2 (A + 2B 2 → AB 4 ), 200 Kcal heat is liberated. When 1 mole of A is completely reacted with excess, of B 2 to form AB as well as AB 4 , 140 Kcal heat is liberated calculate the mole of B 2 used. [Write your answer as number of mole of B 2 used × 10]
Text Solution
Verified by ExpertsGO FOR SOLUTION
(11)
A + 
B 2 
AB, 100 Kcal
x x/2 x
A + 2B 2 
AB 4 , 200 Kcal
(1–x) 2(1–x) (1–x)
100 x + 200 (1–x) = 140
200 – 100 x = 140
x = 
= 0.6
used = 
+ 2(1–x) = 
x 0.6 + 2 (1– 0.6) = 0.3 + 2 x 0.4 = 1.1 mol
1.1 × 10 = 11
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems