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CGP EDU Academic Team
Published on: August 13, 2026
If 27 g of Carbon is mixed with 88 g of Oxygen and is allowed to burn to produce CO 2 , then :
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(b,c,d)
C + O 2
CO 2
mass 27 88
moles

C is limiting reagent
Moles of CO 2 produced = moles of C =
= 2.25
∴ Volume of CO 2 at STP = 2.25 × 22.4 = 50.4 L
Ratio of C and O in CO 2 = 12 : 32 = 3 : 8
Moles of unreacted O 2 = 2.75 – 2.25 = 0.5
∴ Volume of unreacted O 2 at STP = 0.5 × 22.4 = 11.2 L
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