Salt and water is formed by acid-base neutralisation reaction. If ratio of moles of acid & base taken is not similar to the ratio of their stoichiometric coefficient, then one of the component is limiting reagent. Assume no dissociation of water in following reactions. (Base is 80% pure only, take impurity present as inert & non electrolytic) (Molecular mass of Cs = 133, I = 127, Rb = 85.5, Sr = 88)
(i) Select correct combination for the resulting basic solution.
Text Solution
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(i) Mass of pure CsOH = 
= 30 g
CsOH + HI ⎯→ CsI + H 2 O
– –
0.2 mole 0.4 mole
0 0.2 mole 0.2 mole
Base in L.R., [H + ] = 0.2 M [Cs + ] = 0.2 M [I – ] = 0.4 M
(ii) RbOH pure = 
= 41 g
RbOH + HNO 3 ⎯→ RbNO 3 + H 2 O
– –
0.4 mole 0.1 mole
0.3 mole 0 0.1 mole
Acid in L.R., [OH – ] = 0.3M [Rb + ] = 0.4M [NO 3 – ] = 0.1M
(iii) Sr(OH) 2 + H 2 SO 4 ⎯→ SrSO 4 + 2H 2 O [Pure Sr(OH) 2 = 61 × 0.8 = 48.8 gm]
– –
0.4 mole 0.4 mole
– – 0.4 mole
[Sr 2+ ] = [SO 4 2– ] = 0.4 M
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