Published by:
CGP EDU Academic Team
Published on: August 13, 2026
The density (in g mL –1 ) of a 3.60 M sulphuric acid solution that is 29% (H 2 SO 4 molar mass = 98 g mol –1 ) by mass will be:
Text Solution
Verified by ExpertsThe correct answer is:
A
3.6 M solution means 3.6 mole of H 2 SO 4 is present in 1000 ml of solution
∴ Mass of 3.6 moles of H 2 SO 4 is = 3.6 × 98 g = 352.8 g
∴ Mass of H 2 SO 4 in 1000 ml of solution = 352.8 g
Given, 29g of H 2 SO 4 is present in 100 g of solution
∴ 352.8 g of H 2 SO 4 is present in 
× 352.8 = 1216 g of solution
Now density = 
= 
= 1.216 g/mL = 1.22 g/mL
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