Silver metal reacts with nitric acid according to the equation.
3Ag (s) + 4HNO 3 (aq) 
3AgNO 3 (aq) + NO (g) + 2H 2 O (l)
The volume of 1.15 M HNO 3 (aq) required to react with 0.784 g of silver is:
Text Solution
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1.Write the balanced chemical equation:
2.Determine the moles of silver (Ag):
Molar mass of 
Given mass of 
3.Use stoichiometry to find moles of 
required:
From the balanced equation, 3 moles of Ag react with 4 moles of HNO3.
4.Calculate the volume of 
required:
Molarity 
Moles 
Volume
Conclusion
The volume of 
required to react with 
of silver is 
.
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