Phosphoric acid (H 3 PO 4 ) prepared in a twostep process.
P 4 O 10 37.48 g
4H 3 PO 4 . We allow 62 g of phosphorus to react with excess oxygen which form P 4 O 10 in 85% yield. In the step reaction 90% yield of H 3 PO 4 is obtained. Produced mass of H 3 PO 4 is: 149.94 g
Text Solution
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1.Write the balanced chemical equations:
Step : 
Step : 
2. Calculate the moles of phosphorus 
:
Molar mass of 
Moles of 
3. Determine the theoretical yield of 
in step :
According to the balanced equation, 1 mole of 
produces 1 mole of 
.
Therefore, 0.5 moles of 
would produce 0.5 moles of 
.
Molar mass of 
Theoretical yield of 
moles 
4. Calculate the actual yield of 
based on the 
yield:
Actual yield of 
5. Determine the moles of 
used in step :
Moles of 
6. Calculate the theoretical yield of 
in step :
According to the balanced equation, 1 mole of 
produces 4 moles of 
.
Therefore, 0.425 moles of 
would produce 
moles of 
.
Molar mass of 
Theoretical yield of 
moles 
7. Calculate the actual yield of 
based on the 
yield:
Actual yield of 
Therefore, the produced mass of 
is:
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