Published by:
CGP EDU Academic Team
Published on: August 14, 2026
The 'roasting' of 100.0 g of a copper ore yielded 71.8 g pure copper. If the ore is composed of Cu 2 S and CuS with 4.5 % inert impurity, calculate the percent of Cu 2 S in the ore.
The reactions are : Cu 2 S + O 2 
2Cu + SO 2 and CuS + O 2 
Cu + SO 2
Text Solution
Verified by ExpertsThe correct answer is:
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(62%)
Mass of Cu 2 S & CuS = 100 – 4.5 = 95.5 g
Let mass of Cu 2 S is x g.
Cu 2 S + O 2 
2Cu + SO 2
CuS + O 2 
Cu + SO 2
Mass of Cu from Cu 2 S + Mass of Cu from CuS = 71.8
× 63.3 × 2 + 
63.5 = 71.8
x 
= 8.3
x = 
= 62.01 g.
∴ % of Cu 2 S is 62.
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