1120 mL of ozonised oxygen at S.T.P. weigh 1.76 g.

Chemistry Some Basic Concepts of Chemistry The Mole Concept Single Correct MCQ

Published by: CGP EDU Academic Team

Published on: August 13, 2026

It contain 400 mL O 2

It contain 224 mL O 3

It contain 400 mL O 3

It contain 896 mL O 2

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(b,d)

Let the volume of oxygen in 1120 mL of ozonised oxygen be x mL at S.T.P.

∴ Volume of ozone = (1120 - x) mL at S.T.P.

We known that

vol. of mixture × its density = mass

= vol. of oxygen × its density + vol. of ozone × its density

Also, density =

∴ density of oxygen = g/mL (at S.T.P.)

and density of ozone = g/mL (at S.T.P.)

Hence, x × + (1120 – x) × = 1.76

or, 2x + (1120 - x) × 3 = 1.76 × 1400

or, x = (3360 – 2464) mL = 896 mL O 2 .

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