Published by:
CGP EDU Academic Team
Published on: August 13, 2026
60 ml of a mixture of nitrous oxide (N 2 O) and nitric oxide (NO) was exploded with excess of hydrogen. If 38 ml of N 2 was formed, calculate the volume of each gas in the mixture.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(NO = 44 ml ; N 2 O = 16 ml)
Let the volume of NO and N 2 O be a and b ml respectively
N 2 O + NO + H 2 ⎯→ N 2
b a
a + b = 60 ....... (i)
a/2 + b = 38 ....... (ii)
a = 44 ml.
b = 16 ml.
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