Published by:
CGP EDU Academic Team
Published on: August 13, 2026
The total pressure of a mixture of oxygen and hydrogen is 1.0 atm. The mixture is ignited and the water is removed. The remaining gas is pure hydrogen and exerts a pressure of 0.40 atm when measured at the same values of T and V as the original mixture. What was the composition of the original mixture in mole percent ?
A
= 0.2; 
= 0.8
B
= 0.4; 
= 0.6
C
= 0.6; 
= 0.4
D
= 0.8; 
= 0.2
Text Solution
Verified by ExpertsThe correct answer is:
A
Let, Pressure of H 2 = 
Pressure of O 2 = 
given 
+ 
= 1 atm ......
H 2 + 
O 2 ⎯→ H 2 O
initially 
0
final 
– 2 
0 –
Now 
– 2 
= 0.4 atm ......
From eq. &
= 0.8 atm & 
= 0.2 atm
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
If P , V , T represent pressure, volume and temperature of the gas, the correct representation of B…
At constant temperature, in a given mass of an ideal gas
Air at sea level is dense. This is a practical application of
If 20 gas at 1 atm . is expanded to 50 at constant T , then what is the final pressure
Which of the following statement is false
Densities of two gases are in the ratio 1 : 2 and their temperatures are in the ratio 2 : 1, then t…