If in an experiment 100 ml of ozonised oxygen was reduced in volume to 40 ml (at the same temperature and pressure) when treated with turpentine, what would be the increase in volume if the original sample was heated until no further change occurred and then brought back to the same temerature and pressure ?
Text Solution
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at constant T & P
n ∝ v
∴ n = av (a = constant)
given v i = 100 ml V F = 40 ml
∴ n T = 100 a ( turpentine oil absorbs O 3 )
= 40 a
= 60 a
O 3 
O 2
initial moles 60a 0
final moles 0 90a
n' T = 90 a + 40 a = 130 a
∴ v' f = 130 ml & Δ v = 130 – 100 = 30 ml
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