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CGP EDU Academic Team
Published on: August 14, 2026
A 40 ml of a mixture of H 2 and O 2 at 18ºC and 1 atm pressure was sparked so that the formation of water was complete. The remaining pure gas had a volume of 10 ml at 18ºC and 1 atm pressure. If the remaining gas was H 2 , the mole fraction of H 2 in the 40 ml mixture is
Text Solution
Verified by ExpertsThe correct answer is:
A
H 2 +1/2O 2 → H 2 O (l)
a b 0
a–2b 0 b
Reaction is studied at constant P &T.
a+b = 40 a–2b = 10
a = 30 ml b = 10ml
mole fraction of H 2 = volume fraction of H 2 =30/40 = 0.75.
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