(3)

Volume of H 2 O produced = 17 mL; Volume of CO 2 produced = 14 mL

Total volume of CO 2 = volume of CO 2 initially + volume of CO 2 produced = 14 ml

suppose volume of CH 4 and C 2 H 4 in the mixture x and y ml respectively

volume of CO 2 produced on explosion = 14 – (10 – x – y) = (4 + x + y) ml

POAC for C, H and O

for C, 1 × mole of CH 4 + 2 × mole of C 2 H 4 = 1 × mole of CO 2

x + 2y = 4 + x + y y = 4

for H, 4x + 4y = 2 × mole of H 2 O ......... (i)

for O, 2 × mole of O 2 = 2 × (4 + x + y) + mole of H 2 O ......... (ii)

for equation (i) and (ii)

mole of O 2 = (4 + 2x + 2y) (use in explosion)

in explosion reaction

volume of reactant – volume of product = 17 ml

(x + y) + (4 + 2x + 2y) – (4 + x + y) = 17

2x + 2y = 17 ......... (iii)

from equation (i) and (iii)

volume of CH 4 = 4.5, volume of C 2 H 4 = 4 ml, volume of CO 2 = 1.5 ml