Published by:
CGP EDU Academic Team
Published on: August 14, 2026
For two gases, A and B with molecular weights M A and M B , it is observed that at a certain temperature, T, the mean velocity of A is equal to the root mean square velocity of B. Thus the mean velocity of A can be made equal to the mean velocity of B, if
Text Solution
Verified by ExpertsThe correct answer is:
B
Given 
= 
⇒ 8M B = 3 π M A
& 
= 
⇒ 
= 
⇒ M B .T A = M A .T B
⇒ 
M A .T A = M A .T B ⇒ T B > T A Hence
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
The average velocity of gas molecules is 400 m/sec calculate its r.m.s. velocity at the same temper…
At 400 K, the root mean square (rms) speed of a gas X (molecular weight = 40) is equal to the most …
According to kinetic theory gases
The atomic masses of He and Ne are 4 and 20 a.m.u., respectively. The value of the de Broglie wavel…
X and Y are two volatile liquids with molar weights of 10 g mol –1 and 40 g mol –1 respectively. Tw…
A closed vessel with rigid walls contains 1 mol of and 1 mol of air at 298 K. Considering complete…