Published by:
CGP EDU Academic Team
Published on: August 13, 2026
When sulphur in the form of S 8 (g) is heated at 900 K, the initial partial pressure of S 8 (g) which was 1 atm falls by 29% at equilibrium. This is because of conversion of some S 8 (g) to S 2 (g). Find the K p for reaction, S 8 (g)
4S 2 (g).
Text Solution
Verified by ExpertsThe correct answer is:
2
(2.55 atm 3 )
S 8 (g)
4S 2 (g)
time t = 0 1atm 0
At. eq. (1–x) 4x
Pressure of eq. 1 – 0.29 4 × 0.29.
K P =
=
.
K P = 2.55 atm 3 .
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
For the system ⇌ , the expression for equilibrium constant is
In the reversible reaction ⇌ , the concentration of each C and D at equilibrium was 0.8 mole/litr…
4 moles of A are mixed with 4 moles of B. At equilibrium for the reaction ⇌ , 2 moles of C and D …
On a given condition, the equilibrium concentration of and are 0.80, 0.10 and 0.10 mole/litre. Th…
In which of the following, the reaction proceeds towards completion
A reversible chemical reaction having two reactants in equilibrium. If the concentrations of the re…