Home Chemistry Chemical Equilibrium Law of Equilibrium and Equilibrium Constant Two solid compounds A and B dissociate into …
Chemistry Chemical Equilibrium Law of Equilibrium and Equilibrium Constant Single Correct MCQ
Published on: August 14, 2026

Two solid compounds A and B dissociate into gaseous products at 20°C as

(i) A(s) A'(g) + H 2 S(g) (ii) B(s) B'(g) + H 2 S(g)

At 20°C pressure over excess solid A is 50 mm and that over excess solid B is 60 mm find :

A
The dissociation constant of A and B
B
Relative no. of moles of A ′ and B ′ in the vapour phase over a mixture of solid A and B.
C
Show that the total pressure of the gas over the solid mixture would be 39 mm

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Text Solution

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The correct answer is:
CHECK THE SOLUTION.

= 625 mm 2 , = 900 mm 2

A(s) A'(g) + H 2 S(g) B(s) B'(g) +H 2 S(g)

A(s) A'(g) + H 2 S(g) P = 50 mm ⇒ = P A’ = P/2 = 25 mm

B(s) B'(g) +H 2 S(g) P = 60 mm ⇒ = P B’ = P/2 = 30 mm

(i) = (25) 2 = 625 mm 2

= (30) 2 = 900 mm 2

(ii) Ratio of moles is same as that of partial pressure so

A(s) A'(g) + H 2 S(g)

P 1 P 1 + P 2

B(s) B'(g) + H 2 S(g)

P 2 P 2 + P 1

= P A' x = P 1 (P 1 + P 2 ) ......... (i)

= P B' x = P 2 (P 1 + P 2 ) ......... (ii)

= =

(iii) total pressure = P 1 + P 2 + (P 1 + P 2 ) = 2(P 1 + P 2 )

(i) + (ii) = (P 1 + P 2 ) 2

= P 1 + P 2

P T = 2 × ( ) = 39 mm.

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