Published by:
CGP EDU Academic Team
Published on: August 13, 2026
CuSO 4 .5H 2 O(s) 
CuSO 4 .3H 2 O(s) + 2H 2 O(g) K P = 0.4 × 10 –3 atm 2
Which of following statement are correct :
A
Δ Gº = – RT ln 
where 
= Partial pressure of H 2 O at equilibrium.
where = Partial pressure of H 2 O at equilibrium.
B
At vapour pressure of H 2 O = 15.2 torr relative humidity of CuSO 4 .5H 2 O is 100%.
C
In presence of aqueous tension of 24 torr, CuSO 4 .5H 2 O can not loss moisture.
D
In presence of dry atmosphere in open container CuSO 4 .5H 2 O will completely convert into CuSO 4 .3H 2 O
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(b,c,d)
K P = 
= 0.4 × 10 –3 = 4 × 10 –4 atm 2
= 2 × 10 –2 atm
= 2 × 10 –2 atm
= 2 × 10 –2 × 760 = 15.2 torr
Relative humidity = 
× 100 = 100% (If V.P. = 15.2 torr)
When 
> 
backward shift so at 24 torr pressure reaction shift backward.
In dry atmosphere and open container reaction shift completely in forward.
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