Published by:
CGP EDU Academic Team
Published on: August 13, 2026
In the following reaction started only with A 8 , 2A 8 (g) 
2 A 3 (g) + 3 A 2 (g) + A 4 (g) mole fraction of A 2 is found to 0.36 at a total pressure of 100 atm at equilibrium. The mole fraction of A 8 (g) at equilibrium is :
Text Solution
Verified by ExpertsThe correct answer is:
A
2A 8 
2 A 3 + 3 A 2 + A 4
t = 0 2 0 0 0
t = t eq 2 – 2 α 2 α 3 α α
n T = 2 + 4 α
given mole fraction of A 2 is = 0.36.
0.36 = 
α = 0.46
Mole fraction of A 8 = 
= 
= 0.28
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