Published by:
CGP EDU Academic Team
Published on: August 13, 2026
Two solid A and B are present in two different container having same volume and same temperature following equilibrium are established :
In container
A
A(s) 
D(g) + C(g) P T = 40 atm at equilibrium In container 50 atm
D(g) + C(g) P T = 40 atm at equilibrium In container 50 atm
B
B(s) 
E(g) + F(g) P T = 60 atm at equilibrium If excess of A and B are added to a third container having double the volume and at same temperature then, the total pressure of this container at equilibrium is : 100 atm
E(g) + F(g) P T = 60 atm at equilibrium If excess of A and B are added to a third container having double the volume and at same temperature then, the total pressure of this container at equilibrium is : 100 atm
C
200 atm
D
70 atm
Text Solution
Verified by ExpertsThe correct answer is:
B
A(s) 
D(g) + C(g) K p = (20) 2
20 atm 20 atm
B(s) 
E(g) + F(g) K p = (30) 2
30 atm 30 atm
container K p is same so on doubling the volume partial pressure does not change but moles of C, D, E, F will change to maintain their partial pressure. So total pressure = 40 + 60 = 100 atm.
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