Published by:
CGP EDU Academic Team
Published on: August 14, 2026
A 2 B(g) is introduced in a vessel at 1000 K. If partial pressure of A 2 B(g) is 1 atm initially and K P for reaction A 2 B(g) 
2A(g) + B(g) is 81 × 10 –6 then calculate percentage of dissociation of A 2 B.
Text Solution
Verified by ExpertsThe correct answer is:
3
(3)
A 2 B(g) 
2A(g) + B(g)
at t = 0 1 0 0
at eq. (1–x) 2 α α
(partial pressure)
Hence, (1 – α ) 
1
= 81 × 10 –6
α = 3 × 10 –2
percentage of dissociation = 3 ×10 –2 × 100 = 3%
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