Two moles of He gas ( γ = 5/3) are initially at temp 27ºC and occupy a volume of 20 litres. The gas is first expanded at constant pressure until its volume is doubled. Then it undergoes reversible adiabatic change, until the volume become 110 lit, then predict the value of T/100 (where T is the final temperature, 
= 
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Text Solution
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(3)
I st procese is isobaric
volume become double so, T is also become double
So, for adiabatic T i = 2 × 300 = 600
V i = 40
T f = ?, V f = 113
for adiabatic,P 1 V 1 γ = constant = TV γ –1 = constant
T i V i 5/3–1 = T f V f 2/3
600 × (40) 2/3 = T f × (40) 2/3 = T f × (110) 2/3 T f
= 300 K
= 3
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