0.710 g of 
is liberated when 
solution of 
is titrated against KI solution acidified with 
. What is the volume strength of 
solution?
Text Solution
Verified by ExpertsC
The balanced reaction between 
and acidified KI solution can be written as:
1 mole of 
is liberated from 1 mole of 
i.e. 254 g of 
is liberated from 34 g of 
So, 0.710 g of 
will be liberated from 
of 
.
Now, volume strength of 
solution depends upon the amount of oxygen liberated from decomposition of 
of H 
decomposes as:
From the above reaction it is evident that 2 moles of 
upon decomposition give 1 mole of 
gas at NTP.
i.e. 68 g of 
upon decomposition gives 
of 
gas at NTP.
0.095 g of 
will produce 
of 
gas at NTP.
From the information provided in the question, 
contains 0.095 g of 
of 
will liberate 
of 
gas at NTP.
So 
will liberate 
of 
gas at NTP.
Volume strength of provided 
solution 
4.41.
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