Published by:
CGP EDU Academic Team
Published on: August 14, 2026
An excess of acidified potassium iodide solution was added to 250 mL of hydrogen peroxide solution. 0.5 N sodium thiosulphate was consumed by the liberated iodine. The volume strength of the given solution is
Text Solution
Verified by ExpertsThe correct answer is:
D
According to normality equation
or, 
or, 
Strength of 
2 
34 22.41
68g 
22400 mL
68g of 
produce 
at NTP 6.8g of 
produce 
at NTP
Now, 6.8 g of 
is present in 1000 mL of solution.
In other words, 1000 mL of 
gives 2240 mL of 
at NTP
1 mL of 
gives 2240/1000 
22.4 mL of 
at NTP.
So, the volume strength of 
is 22.4.
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