Match the following :
Column-I | Column-II | ||
(a) | HCl < HF | (p) | Strength of hydrogen bonding |
(b) | PH3 < NH3 | (q) | Dipole moment |
(c) | H2O < D2O | (r) | Boiling point |
(d) | F2 < Cl2 | (s) | Bond energy |
Text Solution
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(A – p, q, r, s) ; (B – p, q, r, s) ; (C – p, q, r, s) ; (D – r, s)
Sol. HF shows stronger H-bond than H-Cl.
Dipole moment of HF is more than of HCl. (fact) Due to H-bond, boiling point of H–F is more than that of HCl.
Due to differences in electro negavitivity, the H–F bond is stronger than H–Cl bond.
N is more electronegative than P. So the strength of H-bond is more in NH 3 . Due to this boiling point of NH 3 is more. For the same reason, boiling point and bond energy are also more for NH 3 than PH 3 .
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