Find out the bond order of :
Text Solution
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1 1/2 0 1 (e) 0 (f) 1
Hydrogen molecule (H 2 ) : H 2 : ( σ 1s) 2
Its bond order, therefore, is = 
Cation of hydrogen molecule (H 2 + ) : H 2 + : ( σ 1s) 1
Its bond order, therefore, is = 1/2 (1 – 0) = 1/2
Helium molecule (He 2 ) : He 2 : ( σ 1s) 2 ( σ *1s) 2
Its bond order, therefore, is ½(2 – 2) = 0
Lithium molecule (Li 2 ) : ( σ 1s) 2 ( σ *1s) 2 ( σ 2s) 2
Its bond order, therefore, is 1/2(4 – 2) = 1.
(e) Beryllium (Be 2 ) : ( σ 1s) 2 ( σ *1s) 2 ( σ 2s) 2 ( σ *2s) 2
Its bond order, therefore, is 1/2(4 – 4) = 0.
(f) Boron (B 2 ) : ( σ 1s) 2 ( σ *1s) 2 ( σ 2s) 2 ( σ *2s) 2 ( π 2p 1 x = π 2p 1 y ) ( σ p z ) 0 Its bond order, therefore, is 1/2(6 – 4) = 1.
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