Consider the following statements ;
(I) The hybridisation found in cation of solid PCl 5 is sp 3 .
(II) In AB 2 L 2 type the BAB bond angle is always greater than the normal tetrahedral bond angle.
(III) In ClO 3 – , NH 3 and XeO 3 , the hybridisation and the number of lone pairs on the central atoms are same.
(IV) In P 4 molecule, there are six P–P bonds and four lone pairs of electrons.
of these statements :
Text Solution
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(I) [PCl 4 ] + → sp 3
(II)
has ≈ 102° bond angle due to lp – lp repulsion, as bond pairs are closer to F-atoms.
(III) All have sp 3 hybridisation and one lone pair.
(IV) 
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